SQL Count of columns result for all existing Dates in the table -

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i have table dttransaction , dthoteltransaction transactionid primary key in former , foreign key in later.

columns in dttransaction  :machinename(varchar),bookedon(datetime),transactionid(int)  columns in dthoteltransaction :hcomcid(int) ,transactionid

requirement :

for every bookedon value in dttransaction , want machine name , count of machinename these (415428,415429,415430,415431,415432) hcomcid.

i trying :

select dttransaction.machinename,count(dttransaction.machinename) dttransaction    join dthotelreservation on dttransaction.transactionid =       dthotelreservation.transactionid , dthotelreservation.hcomcid in ( 415428, 415429, 415430, 415431, 415432) convert(varchar(10),bookedon,101)='04/10/2013' group dttransaction.machinename

but give particular date.i want count existing bookedon values.

thanks in advance.

if want sum of dates, remove where clause:

select dttransaction.machinename, count(dttransaction.machinename) dttransaction join      dthotelreservation      on dttransaction.transactionid = dthotelreservation.transactionid ,         dthotelreservation.hcomcid in (415428, 415429, 415430, 415431, 415432) group dttransaction.machinename

if want results date, include in group by. instance, 

select dttransaction.machinename, convert(varchar(10),bookedon,101), count(dttransaction.machinename) dttransaction join      dthotelreservation      on dttransaction.transactionid = dthotelreservation.transactionid ,         dthotelreservation.hcomcid in (415428, 415429, 415430, 415431, 415432) group dttransaction.machinename, convert(varchar(10),bookedon,101) order 1, max(bookedon)

i included order by clause, results in order date within each machine name.


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