html - How to place a DIV regarding to lower left hand-side corner? -

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i add lis in div. div frame fieldset has no width , no height. size should automatically sized using padding. problem div element of class of div:

<div class="flag">     <div id="drop_up">         <fieldset>             <ul>                 <li>                 content                 </li>             </ul>         </fieldset>     </div> </div>

okay, li's inserted automatically through loop.

now problem is, div drop-up frame. size of grows upwards , not downwands usual. can not position using left, bottom etc. because height different depending numbers of li's.

my question if there way position element lower left hand-side corner? positioning takes effect on upper right hand-side corner no problem when div growing downwards.

if there can me out appreciate.

thanks alot.

if understand trying achieve want bottom of 'drop_up' divs attached top of parent 'flag' divs, i.e. no matter how content in either 'flag' or 'drop_up'.

assuming understanding correct suggest wrapping 'drop_up' divs inside div (which call 'drop_upholder') , absolute position new div top of 'flag' div , absolute position bottom of 'drop_up' div holder div.

e.g.

<div class="flag">          <div id="drop_upholder">         <div id="drop_up">             ....             ....         </div>     </div> </div>  .flag #drop_upholder {   position:absolute;   z-index:0;   top:0;   height:0 } .flag #drop_up {   position: absolute;   z-index: 1;   background-color: gray;   padding: 25px;   bottom:0; }

i hope helps.


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