Comparing 2 Arrays in shell script -

i have read contents of folder , store them in array. , need pass array script. how can store , pass array , read array??

#!/usr/bin/ksh  cd /path/applications-war arraywar=( $(ls /path/applications-war)) 

i need contents under folder array (@arraywar). login box , call script. need pass array script.

/usr/bin/ssh -t -t username@machinename /path/myscript.sh @arraywar 

inside myscript.sh, want compare passed array @arraywar servicesarray.

#!/bin/ksh  @arraywar = $1  servicesarray=('abc.war' 'xyz.war')    warfile in @arraywar             if  echo "${servicesarray[@]}" | fgrep  "$warfile";             echo "$warfile matches"        else             echo "$warfile not matched"         fi     done 

here's script, takes variable number of files arguments:

#!/bin/ksh servicesarray=('abc.war' 'xyz.war')  warfile in "${@##*/}"      if  echo "${servicesarray[@]}" | fgrep  "$warfile";         echo "$warfile matches"    else         echo "$warfile not matched"     fi  done 

you call script (note using ls not recommended):

arraywar=( /path/applications-war/* ) /usr/bin/ssh -t -t username@machinename /path/myscript.sh "@{arraywar[@]}" 

you can dispense arraywar, , pass list of files directly

/usr/bin/ssh -t -t username@machinename /path/myscript.sh /path/applications-war/*