python - Function that takes a string as input and counts the number of times the vowel occurs in the string -

so new python , in process of learning basics. trying create function counts number of vowels in string , returns how many times each vowel occurs in string. example if gave input, print out.

   >>>countvowels('le tour de france')         a, e, i, o, , u appear, respectively, 1,3,0,1,1 times. 

i made helper function use, i'm not sure how use it.

def find_vowels(sentence): count = 0 vowels = "aeiuoaeiou" letter in sentence:     if letter in vowels:         count += 1 print count 

and thought maybe use formatting them in write places, not sure notation used example, 1 of lines function be:

   'a, , i, o, , u appear, respectively, {(count1)}, {(count2)}, {(count3)}, {(count4)}, {(count5)} times' 

i not sure how able fit above in function.

you'd need use dictionary store values, since if directly add counts lose information vowel counting.

def countvowels(s):     s = s.lower() #so don't have worry upper , lower cases     vowels = 'aeiou'     return {vowel:s.count(vowel) vowel in vowels} #a bit inefficient, easy understand 

an alternate method be:

def countvowels(s):     s = s.lower()     vowels = {'a':0,'e':0,'i':0,'o':0,'u':0}     char in s:         if char in vowels:             vowels[char]+=1     return vowels 

to print this, this:

def printresults(result_dict):     print "a, e, i, o, u, appear, respectively, {a},{e},{i},{o},{u} times".format(**result_dict)