unix - How to print column offset within each matching line in grep -

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by passing -o -n grep can output matching parts of pattern within file, , line number on each match found.

how can print column offset within line @ pattern found?

i think able mimic same thing you're doing awk. referencing awk manual:

http://www.staff.science.uu.nl/~oostr102/docs/nawk/nawk_92.html

here's file looks like:

this,is,a,test,line this, ,a,test,line,with,the,second,field,blank this, is,another,test,line,with,a,blank,in,the,second,field,but,the,field,isnt,blank this, ,is,another,line,with,a,blank,second,field

and here's command ran:

awk '{regex = "test"; = match($0, regex); print "regex: ",where," on line ",nr}' test

and output:

regex:  11  on line  1 regex:  10  on line  2 regex:  18  on line  3 regex:  0  on line  4

i did quick , dirty, i'm hoping helps enough need be.


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