c++ - bitwise OR int and char -

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i have value know less 16 (no more 4 bits) in int. want bitwise-or char. can this:

c |= i;

or depend on endianness? if problem, this:

c |= (char)i;

solve it?

endianness never matters when doing arithmetic, matters when dealing values (larger 1 char) in other way, i.e. when using char-pointers traverse buffers holding larger values, instance.

in case, there no need cast, automatic arithmetic promotion make sure it's fine. code:

char c = 0; int  =3;  c |= i;

is equivalent to

c = c | i;

the expression computed int, , converted down storage.


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